Calculating radius of the core with just densities

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To calculate the radius of the Earth's core, start by recognizing that the Earth can be modeled as a sphere with an inner core of density Pc and an outer mantle-crust of density Pm. The average density of the Earth (Pe) can be expressed in terms of the volumes and densities of these two regions. Using the gravitational equation g = (GM)/r^2 is not appropriate here; instead, focus on the relationship between mass, volume, and density to derive the core's radius. By setting up the equation for average density, you can solve for the core's radius (rc) in relation to the total radius of the Earth (Re). This approach will yield the desired radius of the core based on the provided densities.
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Homework Statement


Calculate the radius of the Earth's core using the following data:

Pe = 5,515 kg/m^3 (earth's average density)
Pc = 11,000 kg/m^3 (core's density)
Pm = 4,450 kg/m^3 (mantle-crust density)

Re = 6377km (radius of the earth)


Homework Equations


im guessing we should be using the gravitational equation

g = (GM)/r^2 for different shells (might be wrong)

g= gravitational acceleration
G= Gravitational constant
M = mass of sphere with radius of "r"
r= radius


The Attempt at a Solution



i tried the above equation but got no where with this. i need help!
 
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You're dealing with densities, not forces. If the Earth consists of an inner sphere of one density and an outer shell of another density, how would you calculate the average density? Suppose that the inner sphere has radius rc and that the outer shell extends to radius Re (radius of the Earth).
 
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