Calculating Rate of Vaporisation: 240 W Body Heat Loss

AI Thread Summary
The discussion focuses on calculating the rate of vaporization of sweat based on a body heat loss of 240 W during exercise. The latent heat of vaporization is given as 2255 kJ/kg. Participants clarify that 240 W equates to 240 J/s, which is essential for determining the mass of sweat vaporized per second. The correct calculation leads to a result of 106 mg/s for the rate of vaporization. The conversation emphasizes understanding the relationship between power, energy, and mass in the context of heat loss through sweating.
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Homework Statement



During exercise the body loses 240 W of heat due to the evaporation of sweat. Assuming that the latent heat of at body temprature is 2255 kJ/kg, determine the rate of vaporisation of sweat.

answer = 106 mg/s

Homework Equations



L=Q/m

The Attempt at a Solution



What formula do I need to use here? The only formula I can think of is the one with latent heat and heat energy Q=mL. But this formula only gives mass and doesn't give the rate of vaporisation!
 
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If 240J is added to the sweat per second and it takes 2255 000 J to vaporize one kg of sweat, how much is vaporized per second? You don't need any formulas, just logic.
 
ideasrule said:
If 240J is added to the sweat per second and it takes 2255 000 J to vaporize one kg of sweat, how much is vaporized per second? You don't need any formulas, just logic.

I'm not quite sure if I understand correctly, do you mean sweat+240J/2255000? :confused:
 
And it is 240 W not Joules...
 
roam said:
And it is 240 W not Joules...

a Watt is just a Joule per second.
 
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