Calculating Recoil Velocity: Female Character in Diamonds Are Forever

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The discussion focuses on calculating the recoil velocity of a female character in Diamonds Are Forever after firing a gun. For the first scenario, using the bullet's mass of 0.013 kg and its velocity of +702 m/s, the recoil velocity is calculated as -0.19 m/s. In the second scenario, where a blank cartridge ejects a mass of 5.0 x 10^-4 kg at the same velocity, the recoil velocity can be determined using the same formula. The key takeaway is that the method for calculating recoil remains consistent, with only the mass of the bullet changing. Understanding this principle is essential for solving both parts of the problem accurately.
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The lead female character in the movie Diamonds Are Forever is standing at the edge of an offshore oil rig. As she fires the gun, she is driven back over the edge and into the sea. Suppose the mass of a bullet is 0.013 kg, and its velocity is +702 m/s. Her mass (including the gun) is 48 kg.

(a) What recoil velocity does she acquire in response to a single shot from a stationary position, assuming that no external force keeps her in place?

(b) Under the same assumption, what would be her recoil velocity if, instead, she shoots a blank cartridge that ejects a mass of 5.0 10-4 kg at a velocity of +702 m/s?

i know that you take (mass of the bulllet) x (velocity of the bullet) / (mass of the girl) to find the girl's velocity, and it equals -.19 for the first one but i don't know how to do the second part, or if it should also be a negative number.

any help would be appreciated!
 
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The only thing that changes is the mass of the bullet. So figure her velocity in exactly the same way for both parts.
 
that works! thanks!
 
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