Calculating Relativistic Doppler Shift for Moving Radar

AI Thread Summary
The discussion focuses on calculating the relativistic Doppler shift for a radar detecting a car approaching at 135 km/h. The user converted the speed to meters per second and applied the Doppler shift formula, resulting in an unexpectedly large frequency difference of 1.024 x 10^13 Hz. Other participants noted that the formula used is correct, but the resulting value seems unrealistic due to the small ratio of v/c, which may not yield a significant frequency shift. They suggested using a Taylor expansion for small values of v/c to obtain a more accurate result. The conversation emphasizes the importance of proper calculations in relativistic contexts.
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Homework Statement


A car is getting closer to a radar as a speed of 135 km/h. If the radar works at a 2 \times 10 ^{9} Hz, what difference of frequency is observed for the radar?

Homework Equations


\mu=\frac{\mu _0 \sqrt {1- \frac{v^2}{c^2}}}{1-\frac{v}{c}}

The Attempt at a Solution


I converted 135 km/h into m/s, which gave me \frac { 1350 m }{36 s}.
Then I applied the formula and \mu - \mu _0 gave me 1.024 \times 10^{13} Hz which seems WAY too big to be realistic. Am I missing something? Is it a wrong formula?!
 
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The formula is correct and I agree the number is way too large. Can you show how you got it? A word of caution: v/c is too small to plug in a calculator and expect something other than μ0, i.e. no frequency shift. I suggest that you try a Taylor expansion for small values of v/c.
 
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