fluidistic
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Homework Statement
A car is getting closer to a radar as a speed of 135 km/h. If the radar works at a 2 \times 10 ^{9} Hz, what difference of frequency is observed for the radar?
Homework Equations
\mu=\frac{\mu _0 \sqrt {1- \frac{v^2}{c^2}}}{1-\frac{v}{c}}
The Attempt at a Solution
I converted 135 km/h into m/s, which gave me \frac { 1350 m }{36 s}.
Then I applied the formula and \mu - \mu _0 gave me 1.024 \times 10^{13} Hz which seems WAY too big to be realistic. Am I missing something? Is it a wrong formula?!