Calculating Remaining Loan with Differential Equation | DE Question Homework

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Homework Statement



A recent graduate borrowed 19000$ at an annual rate of 5%
to buy a car from a bank. Suppose that it has made an arrangement to pay the bank
r $ per month. Let S(t), measured in $, be the balance due on the loan at ant time
t, measured in years.

Write a differential equation to calculate the amount of loan left to be
paid.

Homework Equations



n/a

The Attempt at a Solution



\frac{dS}{dt} = \frac{S}{20} - 12k

i think this is wrong because something is wrong when i do an explicite solution of S

e\frac{-t}{20}S = 12k(1-e\frac{-t}{20}) + 19000

defenitely something is wrong,

can someone help me how to translate or give some clue the question to

\frac{dS}{dt} form,
 
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FYI, its e-t/20, sorry
 
i've been told that.. bank usually are compound interest... i don't know what that means
 
looks like you have to submit the answer tomorrow, ait?

your answer should :
monthly repayments : RM 754.85
total interest payable : RM5290.92

where
loan amount = RM 40,000
interest rate = 5%
loan term = 5 yrs
repayments = monthly
repayments type = principal & interest

based on this calculator : http://www.banks.com.au/tools/calculator/loan-repayments/

come on BAGINDA, think faster... huhuhuhu
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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