Calculating Resultant Velocity for Two Equal Velocities at Right Angles

  • Thread starter Thread starter thehatchetmen
  • Start date Start date
  • Tags Tags
    Resultant Velocity
AI Thread Summary
To calculate the resultant velocity of two equal velocities at right angles, the velocities are treated as vectors. When two velocities of 100 km/h are at right angles, the resultant velocity is found using the Pythagorean theorem. The calculation involves multiplying one side by the square root of 2, leading to a resultant velocity of approximately 141.4 km/h. This approach confirms that the resultant velocity increases due to the vector nature of the velocities. Understanding vector addition is crucial for solving such problems.
thehatchetmen
Messages
8
Reaction score
0
can someone help me with this question:
Calculate the resultant velocity of a pair if 100 km/h velocities at right angles to each other

i don't even understand what the question is asking me
 
Physics news on Phys.org
Velocities are represented with vectors, so use http://www.codesampler.com/d3dbook/chapter_02/chapter_02_files/image012.jpg" . However, for different vector orientations, you get different resultant velocities.
 
Last edited by a moderator:
k thank you, that helped a lil...would this be the right answer then:

Since both velocities are equal we have to times one of the sides by the square root of 2. Which means that the reluctant velocity is 141.4.
 
Last edited:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top