Calculating Sailboat Acceleration: Solving a Tricky Physics Question

  • Thread starter Thread starter Cowtipper
  • Start date Start date
  • Tags Tags
    Force
AI Thread Summary
To calculate the sailboat's acceleration, the forces acting on it must be analyzed using Newton's Second Law. The wind exerts a force of 390 N north, while the water applies a force of 180 N east. By determining the acceleration components in both directions, the net acceleration can be found using vector addition. The calculation involves using the Pythagorean theorem, resulting in an acceleration magnitude of approximately 1.523 m/s². This approach effectively combines the forces to solve the physics problem.
Cowtipper
Messages
36
Reaction score
0
"The force exerted by the wind on the sails of a sailboat is 390 N north. The water exerts a force of 180 N east. If the boat (including it's crew) has a mass of 270 kg, what is the magnitude and direction of it's acceleration?"

My physics homework was going just dandy until I came to this question.

I am stumped.

Any suggestions, like where to begin?
 
Physics news on Phys.org
You have one force pointing North, so you'll want to find the acceleration in the North direction by using Newton's Second law. Do the same thing for the force pointing East. You'd have two acceleration components of a net acceleration vector. Add the two components vectorially to get the net acceleration, does this help?
 
Do I just use A squared plus B squared = C squared? If so, I get 1.523 as the answer.
 
Cowtipper said:
Do I just use A squared plus B squared = C squared? If so, I get 1.523 as the answer.

That's correct, you have the right idea.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top