Calculating Series Sum: 1/2^n+1/3^n for n=1 | Homework Help"

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Homework Statement



\Sigma (1/2^n+1/3^n)
n=1

Homework Equations





The Attempt at a Solution


I get 7/2
by using a/1-r to both than adding...what am I doing wrong

2+3/2= 7/2
 
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I didn't get 7/2. Your technique seems ok. Must be some calculation error.
 
Lance WIlliam said:

Homework Statement



\Sigma (1/2^n+1/3^n)
n=1

Homework Equations





The Attempt at a Solution


I get 7/2
by using a/1-r to both than adding...what am I doing wrong

2+3/2= 7/2

You are using a/(1-r) with a=1. a is supposed to be the first term in the series. The sum starts at n=1.
 
The standard geometric series starts at n=0. These are not geometric series because they are missing the "n=0" term. Of course, for each of the two series, that would just be 1/20= 1 and 1/30= 1. Since those terms are missing, you need to subtract 2 from your result.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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