Calculating Solution Composition: Isopropanol in Water

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The discussion revolves around calculating the mole fraction, mass percent, and molality of isopropanol dissolved in water. Participants emphasize the importance of showing work to receive effective help and suggest that simply plugging in values into equations may not suffice. The equations for mole fraction, mass percent, and molality are provided, but users are encouraged to demonstrate their understanding and calculations. There is a call for more effort from the original poster to clarify their difficulties. Overall, the thread highlights the need for active engagement in problem-solving to facilitate assistance.
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Homework Statement



A solution is made by disolving 0.40 mol isopropanol (C3H7OH) in 0.70 mol water.
(a) What is the mole fraction of isopropanol?

(b) What is the mass percent of isopropanol?
%
(c) What is the molality of isopropanol?
m



Homework Equations





The Attempt at a Solution




Not sure what steps to take here?
 
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Whoa man why are you posting so many times, if they don't answer they don't answer. I've been waiting for an answer, if someone knows then they'll hopefully help you if not? posting 20 times won't help.
 
Do you know the definitions of each of those quantities? Can you show the equations for them? Check your book. Tell us what is giving you trouble. You need to show more effort, we can't do all the work for you!
 
mole fraction= amount (mol) of solute / amount (mol) of solute + amount (mol) of solven

mass percent= mass of solute/ mass of solute + mass of solvent x 100

molality = amount mol of solute/ mass kg of solvent


i know the equations do i just plug the quantities in or is there more to it than that
 
jdhutto said:
i know the equations do i just plug the quantities in or is there more to it than that
show more work in your post(s) and we'll be glad to help :)

it won't help you very much if we just direct you straight to the answerrr
 
i know the equations do i just plug the quantities in or is there more to it than that

Just try to do the calculations. Look at what the equation is asking for. Was it given to you in the question? Do you have to do some calculations to get those quantities in the equation? The best way to get help is to show your work. That way we can see what you're not understanding.
 
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