Calculating Speed for a Bullet to Pass Through 10 Planks

  • Thread starter Thread starter The legend
  • Start date Start date
  • Tags Tags
    Bullet Speed
AI Thread Summary
To determine the speed required for a bullet to pass through 10 planks, it is established that the bullet's final speed squared is proportional to the distance penetrated. Using the equation v² - u² = 2as, where the initial speed (u) is 10 m/s, the calculation shows that v² must equal 1000 for 10 planks. This leads to the conclusion that the necessary speed is 10 times the square root of 10. The discussion confirms the validity of this approach and suggests an alternative method using the work-energy theorem. The calculations and reasoning presented are sound for solving the problem.
The legend
Messages
420
Reaction score
0

Homework Statement


A gunman shot a bullet with a speed of 10ms-1 which just penetrates into a plank of wood. So with what speed should he fire the bullet so that it passes through 10 similar planks?


Homework Equations


Newtons equations of motion.


The Attempt at a Solution


v2 - u2 = 2as
v2 is directly proportional to s

So,
v21/v22 = s1/s2

That means
v22 = 10*10*10
Therefore
v = 10 root 10



Well that's what I have done but I aint sure!
 
Physics news on Phys.org
Welcome to PF!

Hi The legend! Welcome to PF! :smile:

(have a square-root: √ :wink:)
The legend said:
v2 - u2 = 2as
v2 is directly proportional to s

v = 10 root 10

Yes, that's fine! :smile:

(btw, you could also have used the work-energy theorem … change in KE = work done = force x distance, is proportional to distance :wink:)
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top