Calculating Speed of Bowling Ball Down Incline

AI Thread Summary
To calculate the translational speed of a bowling ball rolling down an incline, the conservation of energy principle is applied, equating potential energy at the top with kinetic energy at the bottom. The relevant equation includes gravitational potential energy (mgh) and both translational (1/2mv^2) and rotational (1/2Lw^2) kinetic energy. It is crucial to differentiate between initial and final states, noting that initial velocities are zero. Additional equations for the moment of inertia (I) and angular velocity (ω) are necessary for a complete solution. The energy at both positions must remain equal to find the final speed accurately.
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Homework Statement


a bowling ball with a mass of 5.45kg and a radius of .191m starts from the rest at a height of 1.8m and rolls down a 22.3m slope. what is the translational speed of the ball when it leaves the incline.


Homework Equations



E=mgh +1/2mv^2+1/2Lw^2

The Attempt at a Solution


E=5.45kg*9.81m/s*1.8m+ 1/2 %.45kg* v^2+1/2 Lw^2
?is this even right?
 
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Hi physicsgurl12! :smile:

physicsgurl12 said:

Homework Equations



E=mgh +1/2mv^2+1/2Lw^2

The Attempt at a Solution


E=5.45kg*9.81m/s*1.8m+ 1/2 %.45kg* v^2+1/2 Lw^2
?is this even right?

You need more relevant equations.
That is, you need one for L (although the symbol is usually I), and you need one for w (for which the symbol is usually ω).
Can you get those?

Furthermore you need to make a distinction between the initial position, where v and w are zero, and the final position, where h is zero.

The energy E in both the initial position and the final position must be the same.
 
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