Calculating Spherical Harmonics Cuadratic Dispersion

AI Thread Summary
The discussion focuses on calculating quadratic dispersion in quantum systems by expanding x^2 in terms of spherical harmonics using Clebsch-Gordan coefficients. The user initially expands x as a linear combination of spherical harmonics but encounters issues when squaring x to obtain the correct form of x^2. Despite achieving a sum of spherical harmonics multiplied by coefficients, the results are incorrect. The user seeks assistance in resolving this calculation challenge. The thread highlights the complexities of applying spherical harmonics in quantum mechanics.
altered-gravity
Messages
62
Reaction score
0
Greetings,

I´m calculating cuadratic dispersion of some quantum systems. I need to expand x^2 in terms of spherical harmonics (using Clebsch-Gordan coefficients, or threeJ as well) in order to be able to use Gaunt espression in the integral solving.

I start from the expansion of x as linnear combination of Spherical Harmonics (with Clebsch-Gordan coef.). Then, in order to get x^2, I calculate x*x (studying the couplings of the state vectors term by term) and I get what I need: a sum of Spherical Harmonics (each multiplied by a C-G coef.) but it´s not the correct one!

Could anyone help me? Thanks
 
Physics news on Phys.org
wow K-12 got really hard really fast!
sorry, maybe a different forum should be addressed
 
oops! Excuse me.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top