Calculating Tension in a 2 Mass System

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SUMMARY

The discussion focuses on calculating the acceleration and tension in a two-mass system involving M1=3.0 kg and M2=2.5 kg. The acceleration was correctly calculated as 1.24 m/s² using the equation Asys = (M2 * g - M1 * g * sin(θ)) / (M1 + M2). For the tension in the string, the user initially misapplied the formula but later corrected it to T = M1(g) - (M1 * Asys), leading to a tension value of -0.127 N, indicating a misunderstanding of the tension's directionality.

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  • Understanding of Newton's Second Law of Motion
  • Basic knowledge of forces and tension in strings
  • Familiarity with gravitational force calculations
  • Ability to manipulate algebraic equations
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  • Learn about free-body diagrams for analyzing forces
  • Explore the effects of angles on tension calculations
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Homework Statement



In the ideal setup showin in the following figure, M1=3.0 kg and M2=2.5KG
A) What is the acceleration of the 2 mass system?
B) What is the tension in the string?

Homework Equations


Asys=M2 * g - M1 * g (sin[tex]\oslash[/tex]) / M1 + M2


The Attempt at a Solution



Calculated the acceleration of the system using above equation and obtained:

Asys=1.24 m/s^2

My teacher gave me full credit on that part of my answer. On part B, however, I was expected to find the tension on the string. Here's what I attempted:
Asys=M1(g) -T / M1
1.24 m/s^2 = 2.5(9.8) - T / 5.5 kg

I am thinking I need to also divide by mass 2? Either way, I think I could use a fresh approach at thinking about tension. To me, it just seems like the transferred force through a string...I guess I'm a bit confused.

Thanks in advance,

Ian
 

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Asys=M1(g) -T / M1
1.24 m/s^2 = 2.5(9.8) - T / 5.5 kg


1.24 m/s^2 = [2.5(9.8) - T] / 2.5 kg Try this one and find T
 
Wow, tell me my mistake wasn't that simple...My new T= -0.127

Thanks guys...I can't even believe I didn't see that!
 

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