Calculating Tension in a Rope for a Slowing Object

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To calculate the tension in a rope lifting a bucket that is slowing down at a rate of 0.640 m/s², the weight of the bucket is given as 22.0 N. The mass of the bucket is determined to be 2.24 kg using the formula Fg = M * g, where g is the acceleration due to gravity (9.8 m/s²). The total effective acceleration acting on the bucket is 10.44 m/s², which combines the gravitational force and the deceleration. Using the formula Ft = M * A, the tension in the rope is calculated to be 23.39 N. A force diagram is recommended for clarity in solving for tension.
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Homework Statement


A bucket is lifted up by a rope, slowing down at a constant rate of 0.640 m/s^2. Find the tension in the rope if the bucket weighs 22.0 N.

Homework Equations


F=MA
Fg(gravity)=M*G(gravitational force)

The Attempt at a Solution


9.8 m/s^2 + 0.640 m/s^2 = 10.44 m/s^2
22N=M*9.8m/s^2
M=2.24 kg

Ft=MA
Ft=2.24 kg * 10.44 m/s^2
Ft=23.39 N
 
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badshar said:

Homework Statement


A bucket is lifted up by a rope, slowing down at a constant rate of 0.640 m/s^2. Find the tension in the rope if the bucket weighs 22.0 N.

Homework Equations


F=MA
Fg(gravity)=M*G(gravitational force)

The Attempt at a Solution


9.8 m/s^2 + 0.640 m/s^2 = 10.44 m/s^2
22N=M*9.8m/s^2
M=2.24 kg

Ft=MA
Ft=2.24 kg * 10.44 m/s^2
Ft=23.39 N

Everything is all scrambled up. Why are you adding accelerations? Draw a force diagram. The tension T points up, the weight W points down and you know the acceleration. Try and solve for T.
 
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