Calculating Tension in Ropes A & B

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A 1 kg ball is suspended by rope A, while a 2 kg ball is connected to it via rope B, both accelerating upwards at 4.0 m/s². The tension in rope A is calculated to be 41.4 N, while the tension in rope B is 27.6 N. The calculations consider the gravitational force and the additional force due to acceleration. The discussion emphasizes the importance of understanding the forces acting on the ropes and suggests using a free body diagram for clarity. Overall, the approach to solving the problem is confirmed as correct.
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Homework Statement


I have a 1 kg ball hanging from rope A, and a 2 kg ball connected to the 1 kg ball by rope B. They are accelerating up at 4.0 m/s^2. I need to know the tension in rope A and rope B.


Homework Equations


Tension = Fg + ma ?


The Attempt at a Solution


Rope A: (1 kg + 2 kg) * (9.8 m/s^2) + (1 kg + 2 kg) * (4 m/s^2) = 41.4 N
Rope B: (2 kg) * (9.8 m/s^2) + (2 kg) * (4 m/s^2) = 27.6 N

Am I doing this correctly?
 
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I think since the ropes are accelerating in the vertical direction , the sum of all forces acting on the ropes with the attached ball will be equal to an accelerating force, not zero. Have you sketched a free body diagram of all the forces acting upon the two ropes? .
 
Last edited:
jamessmith said:

The Attempt at a Solution


Rope A: (1 kg + 2 kg) * (9.8 m/s^2) + (1 kg + 2 kg) * (4 m/s^2) = 41.4 N
Rope B: (2 kg) * (9.8 m/s^2) + (2 kg) * (4 m/s^2) = 27.6 N

Am I doing this correctly?
Looks good! :smile:

p.s. Welcome to Physics Forums.
 
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