Calculating the current in a solenoid

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To calculate the current in a rotating solenoid in a magnetic field, one must first determine the induced voltage using Faraday's law of induction. The magnetic field strength, B, is essential for this calculation, and the problem can be approached by treating the solenoid as a series circuit with resistance R and inductance L. Once the induced sinusoidal voltage is established, the current can be expressed as a function of time. There is a noted error in the referenced HyperPhysics page that could affect understanding. The discussion emphasizes the importance of correctly applying the equations related to electromagnetic induction.
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Homework Statement



A short-circuited solenoid of radius b with n turns rotates at an angular velocity
about the diameter of one of the turns in a uniform magnetic field B. The axis of rotation is perpendicular to the magnetic field direction. The resistance and the inductance of the solenoid are equal to R and L, respectively. Find the current in the solenoid as a function of time

Homework Equations



Hint eq: phi = normal vector (dot) Magnetic field (B) s


The Attempt at a Solution



i can't seem to figure out where to start. in order to find the current in the solenoid, do i have to first start with finding the magnetic field (or a specific value of B)? and then plug that into the above eq?
 
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See the first page of,

http://hyperphysics.phy-astr.gsu.edu/hbase/electric/farlaw.html

There is a small error in the first page of the link above, can you find it?

Once you get the induced sinusoidal voltage you can treat the problem as a series circuit consisting of a sinusoidal voltage a resistance and an inductor?

Found via,

http://www.google.com/webhp?hl=en#h...w.,cf.osb&fp=e47bbecef463087a&biw=721&bih=408

See also,

http://www.google.com/search?hl=en&...&um=1&ie=UTF-8&tbm=isch&source=og&sa=N&tab=wi
 
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