Calculating the Gravitational Potential of a Spehrical Shell

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Discussion Overview

The discussion revolves around the mathematical derivation of gravitational potential due to a hollow spherical shell as presented in The Feynman Lectures on Physics. Participants explore the concepts of gravitational potential energy, the geometry involved in the derivation, and the specific variables used in the equations.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Homework-related

Main Points Raised

  • One participant expresses difficulty in understanding the mathematics related to the gravitational potential of a hollow spherical shell, particularly the role of the variable y and the sine function in the equations.
  • Another participant suggests referring to the diagram accompanying the equations for clarification on the variables x and y.
  • A clarification is provided that y represents the perpendicular distance of the ring from a specified line, and that the thickness of the ring along the x-axis is related to the sine of the angle theta.
  • A participant confirms their understanding after receiving clarification on the mathematical relationships involved.

Areas of Agreement / Disagreement

Participants generally agree on the interpretation of the variables and the mathematical relationships once clarified, but initial confusion regarding the derivation indicates that some aspects remain complex and not fully resolved for all participants.

Contextual Notes

The discussion highlights the importance of visual aids, such as diagrams, in understanding complex mathematical derivations in physics. There may be assumptions regarding the reader's familiarity with the material that are not explicitly stated.

Who May Find This Useful

Students and enthusiasts of physics, particularly those studying gravitational theory and mathematical derivations in classical mechanics.

amolv06
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I'm going through The Feynman Lectures On Physics. I've taken a few classical physics classes before, however Feynman's detailed explanations are much better than anything I've gotten from my teachers. However, I'm having a little difficulty following the mathematics when he tries to show that a hollow spherical shell acts as though it has all its mass located at the center.

I will read the paragraph previous to the math I am having difficulty with, and then read off the math.

"We now demonstrate the correctness of this miracle. In order to do so, however, we shall consider a thin uniform shell instead of the whole earth. Let the total mass of the shell be m, and let us calculate the potential energy of a particle of mass m' a distance R away from the sphere and show that the potential energy is the same as it would be if the mass m were at the center. If we call x the distance of a certain plane section from the center, then all the mass that is in a slice dx is at the same idstance r from P, and the potential due to the ring is -Gm'dm/r. How much mass is in the small slice dx? An amount

[tex]dm=2*pi*y*mu*ds=\frac{2*pi*y*mu*dx}{sin(\vartheta)}=\frac{2*pi*y*mu*dx*a}{y}=2*pi*a*mu*dx[/tex]

Here, a is the radius I believe. I don't know where he pulled y from. Mu is the density of a piece of the spherical shell.

What I can't understand is how he is doing the math for all this. Where does the sin theta come from? I'm slightly lost here.

This is in the Feynman Lectures, by the way.
 
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Can you tell me the chapter it's in, I have to see it in the book. I'll try to see if I can figure it out.
 
It's in chapter 13-4. Thanks.
 
amolv06 said:
Here, a is the radius I believe. I don't know where he pulled y from. Mu is the density of a piece of the spherical shell.

What I can't understand is how he is doing the math for all this. Where does the sin theta come from? I'm slightly lost here.
To understand what he's doing, refer to the diagram next to the equations. The diagram shows the meaning of x and y.

dm refers to the mass of the ring-shaped slice of the sphere. Yes, a is the radius of the sphere. y is the perpendicular (vertical) distance of the ring from the line O-P. Since ds is the length of the side of the ring, the thickness of the ring along the x-axis (which is the line O-P) is [itex]dx = ds \sin\theta[/itex].
This is in the Feynman Lectures, by the way.
Book I, chapter/page 13-9.
 
Ahh. That makes perfect sense now. Thanks a lot.
 

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