Calculating the Limit of an Infinite Series

AI Thread Summary
The infinite series 2/3! + 4/5! + 6/7! + ... converges to e^-1. To solve such problems, it's helpful to relate the series to known infinite series, particularly those involving the exponential function e. By analyzing the terms of the series, one can identify patterns that align with the series expansion of e or e^-1. This approach simplifies the calculation and leads to the conclusion that the limit of the series is indeed e^-1. Understanding these connections is crucial for tackling similar problems in infinite series.
kayron
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Homework Statement





2/3!+4/5!+6/7!+...to infinity is equal to?
 
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Have you done any problems similar to this? Where are you getting stuck?
 
yes i have.
the trick is to translate this into an expression of known a known infinite series, like that of e or e^-1
here the answer is e^-1
 
Write down e and e^-1, what do you find?
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

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