Calculating the Mass of a Cycloid Wire with Constant Density | Integration Help

  • Thread starter Thread starter kasse
  • Start date Start date
  • Tags Tags
    Mass Wire
Click For Summary

Homework Help Overview

The problem involves calculating the mass of a wire shaped like a cycloid with a constant density. The original poster seeks to integrate a function related to the arc length of the cycloid to find the mass.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to determine the mass by integrating the product of density and arc length differential. They express uncertainty about the integration process and the correctness of their expression for ds. Other participants suggest using trigonometric identities to simplify the integration.

Discussion Status

Participants are exploring different approaches to the integration, with some offering insights into trigonometric simplifications. There is a mix of attempts at finding the mass and discussions about related calculations, such as finding the centroid.

Contextual Notes

There is an emphasis on using specific trigonometric identities and formulas, with some participants questioning the relationships between different expressions. The original poster's integration setup and assumptions are under discussion, but no consensus has been reached.

kasse
Messages
383
Reaction score
1

Homework Statement



What is the mass of a wire shaped like the arch x=t-sint, y=1-cost (t from 0 to 2*pi) of a cycloid C that has constant density D=k?

The Attempt at a Solution



I must integrate D*ds. I find that ds=sqrt(2-2cost)dt. Is this wrong? If it's right, I don't know how to integrate k*sqrt(2-2cost).
 
Last edited:
Physics news on Phys.org
There is a trick. sqrt(1-cos(t)) can be written neatly in terms of sin(t/2). Check out half angle formulas.
 
m=8k is my answer then.
 
Last edited:
Dick said:
There is a trick. sqrt(1-cos(t)) can be written neatly in terms of sin(t/2). Check out half angle formulas.

I think it's supposed to be sqrt((1-cos(t))/2) that can be written in terms of sin(t/2), right?
 
Right. I didn't mean that they were equal - just that they were closely related.
 
Then I'll try to find the centroid, first the x:

Then I must integrate x*k*ds and multiply with 1/m=1/8k.

If I've done right, I'll have to integrate (t-sin(t)*sin(t/2). Is it time for another trick?
 
Not as tricky as the first one. t*sin(t/2) is a routine integration by parts. I would write sin(t)*sin(t/2) as 2*sin(t/2)*cos(t/2)*sin(t/2) using double angle formula and do a substitution. Nothing unusual here.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
20
Views
2K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 105 ·
4
Replies
105
Views
11K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
3
Views
2K