Calculating the Maximum Safe Volume of Ethanol in a Confined Space

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To calculate the maximum safe volume of ethanol in a confined space, it's essential to understand that the lower flammability point of ethanol is 3.5% v/v. For a 100-liter vessel, this means that 3.5 liters of vapor can make the space ignitable. By assuming the vapors behave like an ideal gas, one can determine the number of moles in 3.5 liters using the formula N=3.5/22.4. Multiplying the number of moles by the molar mass of ethanol provides the mass, which, when divided by the density of liquid ethanol, yields the corresponding liquid volume. This method ensures that the ethanol volume remains below the flammability threshold.
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Hello
The lower flammability point of ethanol is 3.5% v/v. How can I work out the max volume of ethanol in a specified space to be lower than the flammability point
Eg
If I have a 100l vessel 3.5% will be 3.5l of vapour in that 100l vessel that will make it ignitable - how can I convert 3.5 l of ethanol vapour back to the volume of ethanol as liquid(pressure and t at ambient at this point)
Thank u
 
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You can have an estimate by assuming the vapors behave like an ideal gas.
In normal conditions, you can find the number of moles in 3.5 L of vapors like
N=3.5/22.4
Then multiply by molar mass o get the mass of ethanol in these 3.5 L.
And knowing the mass and density of liquid you can find the volume of liquid.
 
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