Calculating the number of quantum states in the valence and conduction bands

  • Engineering
  • Thread starter jisbon
  • Start date
  • #1
462
30

Homework Statement:

Calculate the number of quantum states per cm cube in GaP in the valence and conduction band, given that the mass density is 4.13g/cm^3

Relevant Equations:

-
Hi all,
This question asks me to calculate the number of quantum states, as well as electrons per cm^3 of the crystal in the room temperature.
The problem is I only dealt with a single element before without any calculation for 1cm^3 whatsoever. For example for a Silicon semiconductor, I can determine that a-Si atom share four valence electrons (2 from its 3s and 2 from 3p states) to form a stable configuration, hence only the 3s and 3p states are involved, whereby the number of states, in this case, is 8N (2+6) from the 3s and 3p state, whereby the upper band contains 4N states and lower band aka the valence band contain 4N states.

So in the question I presented, I will need to calculate the number of atoms/cm^3 to find what is N first. Hence, first, amt of GaP = mass/Mr. Hence in 1cm^3, I can find that the amount = 4.13/(69.72+30.974) = 0.0410 mol = 2.469*10^22 atoms. So N = 2.469*10^22

Now here comes the problem, how many N states are there? Since now there are 2 elements, how do I combine them together to form a lattice if GaP does not have any spare valence electrons to bond with other GaP atoms to form the crystal lattice? How can I find what are the states involved in GaP for bonding with other GaP atoms?

Thanks
 

Answers and Replies

Related Threads on Calculating the number of quantum states in the valence and conduction bands

Replies
0
Views
2K
  • Last Post
Replies
8
Views
8K
Replies
1
Views
651
Replies
0
Views
2K
Replies
0
Views
5K
Replies
1
Views
3K
Replies
1
Views
414
  • Last Post
Replies
3
Views
1K
Top