Calculating the Radius of a Banked Curve Using Newton's Second Law

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The discussion focuses on calculating the radius of a banked curve using Newton's second law. A car navigating a curve at a speed of 23.0 m/s on a banked road with a 27.0° angle requires an analysis of forces, specifically the normal force and gravitational force components. Initially, the user attempted to apply the formula R = (v^2)/cotθ but found it incorrect. After further discussion, it was clarified that the correct formula is R = (v^2)/(tanθ g), which accounts for the angle and gravitational acceleration. This highlights the importance of correctly identifying the components of forces acting on the car.
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can someone please help me, i can't figure out where the angle on the free body diagram for this problem. i was thinking of using Newton's second law with a = v(squared)/R would this work?

A car goes around a curve on a road that is banked at an angle of 27.0°. Even though the road is slick, the car will stay on the road without any friction between its tires and the road when its speed is 23.0 m/s. What is the radius of the curve?
 
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Do the forces analysis and find which force component is working as the centripetal force.
 
well there is no friction force so the only thing pushing it to the center would be the acceleration, is that right?
 
Actually it will be a component of the normal force, try to draw all the forces on our particle, Normal and weight.
 
oh ok so
sumF = Ncosθ = m ((v^2)/R)

sumFy = Nsinθ - mg = 0

i used this and i solved for R = (v^2)/cotθ but i didn't get the correct answer. can you please tell me what i did wrong?
 
Ncos\theta = mg

Nsin\theta = ma_{c}

Look at the triangle...
 
oh i get it. its R = (v^2)/(tanθ g)
thank you for your help!
 
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