Calculating the Ratio of Electromagnetic Wave Speeds in Vacuum and Materials

AI Thread Summary
The discussion focuses on calculating the ratio of electromagnetic wave speeds in vacuum versus materials using the relationships between permittivity and permeability. The speed of light in vacuum is defined as c = 1/sqrt(ε0μ0), while in materials, the speed v is expressed as v = 1/sqrt(εμ). The ratio of these speeds is given by c/v = 1/sqrt(κκm), where κ is the dielectric constant and κm is the relative permeability of the material. Participants clarify the correct application of these formulas and relationships, ultimately confirming the calculations. The conversation emphasizes the importance of substituting the material properties correctly to derive the desired ratio.
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Homework Statement



Electric and magnetic fields in many materials can be analyzed using the same relationships as for fields in vacuum, only substituting relative values of the permittivity and the permeability, ε = κε0 and μ = κmμ0, for their vacuum values, where κ is the dielectric constant and κm the relative permeability of the material. Calculate the ratio of the speed of electromagnetic waves in vacuum to their speed in such a material. (Use the following as necessary: κ, κm, ε0, and μ0.)

The Attempt at a Solution



c= sqrt(epsilon0*mu0)
and by analogy,
v= sqrt(/epsilon/mu)
So,
c/v = 1 / sqrt ( kappa * kappa m)


would the c = 1/ sqrt( epsilon0*mu0)

that would give me 1/(epsilon*mu0)

either of them are wrong..
any hint?
 
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yjk91 said:
c= sqrt(epsilon0*mu0)
and by analogy,
v= sqrt(/epsilon/mu)
So,
c/v = 1 / sqrt ( kappa * kappa m)
Not quite. The relationship between the permeability and permitivity and c is
c = \frac{1}{\sqrt{\epsilon_o \; \mu_o}}
Make use of the fact that in the material \epsilon = \kappa \epsilon_o and \mu = \kappa_m \mu_o
 


i got it thanks always helping :)
 
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