Calculating the speed of an object

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To calculate the speed of an object on a merry-go-round with an 11-meter radius taking 15 seconds for one complete revolution, the circumference is first determined using the formula C = 2πr, resulting in approximately 69.12 meters. The speed is then calculated by dividing the distance traveled in one trip by the time taken, yielding a speed of about 4.61 meters per second. Some participants question the need to multiply by two trips, as the problem specifies only one complete revolution. Clarification on the time period and angular velocity is also sought to ensure accurate calculations. The discussion highlights the importance of correctly interpreting the problem's parameters for accurate speed determination.
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Homework Statement


If the radius of a merry-go-round is 11 meters, and it takes 15 seconds to go around once, what is the speed of an atom at the outer rim?

Homework Equations


C = 2 \pi r
v = m / s

The Attempt at a Solution



C = 3.14 * 22
(gives distance traveled, 1 trip)
Multiply by 2 (i.e. 2 trips as indicated by problem)
divide by the time, 15s
Answer was told to be wrong, I thought it rather simple, did I make a calculation error somewhere?
 
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Nal101 said:

Homework Statement


and it takes 15 seconds to go around once


so what is the time period? What is the angular velocity when you get that?
 
Nal101 said:
Multiply by 2 (i.e. 2 trips as indicated by problem)
Where does it say this?
 

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