Calculating the Total Energy of a Geosynchronous Satellite in Orbit

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To calculate the total energy of a geosynchronous satellite with a mass of 1500 kg at a height of 325 km, the relevant equations include kinetic energy (Ek) and gravitational potential energy (Ep). The total energy (Et) is derived from the equation Et = Ek + Ep, where Ek is calculated as 1/2(mv^2) and Ep as -G(Mem)/r. The correct orbital radius is determined by adding the Earth's radius to the satellite's height. After correcting the calculations, the total energy is found to be approximately -1.82 x 10^12 J. Accurate understanding of gravitational forces and orbital mechanics is essential for these calculations.
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Homework Statement


Calculate the total energy of a geosynchronous satellite (one that orbits over a fixed spot) with a mass of 1500kg, orbiting Earth at a height of 325km with an orbital speed of 5000m/s

Homework Equations


Et= Ek-Ep
Et= -1/2(GMem)/r


The Attempt at a Solution


im guessing the answer should be negative, using the mass of Earth being 5.98*10^24, but its wielding an incorrect answer constantly ,im getting Et= 8.9*10^10J ( i calculated radius being... r= radius of Earth + height= 6.7*10^6 m, am i suppose to use a different mass instead of the mass of earth, thank you
 
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how would you find orbital height? quite confused thank you for the help
 
At a geosynchronous orbit you can figure the required orbital velocity to match the Earth's rotation, one orbit every 24 hours. We want the centripetal force equal the force of gravity,

F = GmM/R^2 = mv^2/R
 
yes , its orbiting Earth at 325km or 3.25*10^5m
Et= kinetic + potential energy= (mv^2/r- GMem/r^2) is that correct?
 
sorry, kinetic is 1/2(mv^2)
 
Cudi1 said:
yes , its orbiting Earth at 325km or 3.25*10^5m
Et= kinetic + potential energy= (mv^2/r- GMem/r^2) is that correct?

Looks good except the potential energy goes as 1/r.
 
oh , so it would be Et= 1/2(mv^2) - (GMem/r) and thank you for the help
im getting the total energy is -1.82*10^12j
 
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