Calculating the Value of an Infinite Series

AI Thread Summary
The discussion focuses on calculating the value of the infinite series 1 + (1/3)² + (1/5)² + (1/7)² + ... The series is expressed in terms of the sum of the squares of odd numbers, which requires a different approach than using the sum of even numbers. It is suggested to define a second series K for the sum of the inverse squares of even numbers, allowing the relationship S + K = Σ(1/i²) to be established. By calculating K and subtracting it from the total sum, the value of the original series S can be determined. The series converges absolutely, which is crucial for the validity of these calculations.
tommyhakinen
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Homework Statement


What is the value of:
1 + (\frac{1}{3})^{2} + (\frac{1}{5})^{2} + (\frac{1}{7})^{2} + (\frac{1}{9})^{2} + ...
 
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Use the following:
<br /> \sum_{i=1}^\infty \left(\frac{1}{2i}\right)^2 = \frac{1}{4}\sum_{i=1}^\infty \frac{1}{i^2}.<br />​

You will need to rely on the fact that the series converges absolutely. (Why?)
 
Tedjn said:
Use the following:
<br /> \sum_{i=1}^\infty \left(\frac{1}{2i}\right)^2 = \frac{1}{4}\sum_{i=1}^\infty \frac{1}{i^2}.<br />​

You will need to rely on the fact that the series converges absolutely. (Why?)

That won't work. The series in question has squares of odd numbers in the denominator.

Let the given series be S. Now, let us assume that there is another series K which is the sum of all the inverse squares of the even numbers till infinity.

Now, S+K=\sum \frac{1}{i^2}

This series K is the series that Tedgin pointed out. You can calculate S+K, and K. Subtract the two and you get your answer.
 

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