Calculating Thermal Beam Deflection for Space Boom Arm Design

AI Thread Summary
The discussion focuses on calculating thermal beam deflection for a space boom arm design, specifically when the top side of the beam reaches 300 degrees while the bottom remains at zero. The initial equation for deflection, delta=(thermal constant*length^2*temp change)/thickness, is noted as applicable for temperature differences at the ends of the beam rather than the sides. A derivation yields a cantilever tip deflection formula, y = 0.5*alpha*(L^2)(Tb - Tt)/h, where parameters include the coefficient of thermal expansion, cantilever length, and temperature differences. The analysis incorporates bending and axial strains to derive effective stress and moment, leading to a final deflection equation of delta = alpha*Delta T*L^2/2h for small deflections. This approach provides a method for accurately assessing deflection in the context of the project.
dmalwcc89
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Hey I am working with a group on a project where we basically have to design a boom arm for use in space. We've got most of the project figured out but there is a section where we have to determine the beam's deflection if the top side of the beam reached a 300 degree temperature while the bottom side was fixed at zero.

Obviously I've seen the equation delta=(thermal constant*length^2*temp change)/thickness but that is reresentative of when the two beam ENDS are differing temperatures, not the two beam SIDES as in my case.

My question is what equation would I be looking at to determine this information?
 
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I tried a quick derivation (too lengthy to show here), and got a cantilever tip deflection of y = 0.5*alpha*(L^2)(Tb - Tt)/h, where alpha = coefficient of thermal expansion (CTE), L = cantilever length, h = cantilever depth, Tb = temperature of cantilever bottom fiber, and Tt = temperature of cantilever top fiber.
 
I get the same answer as nvn, by assuming a bending strain of \epsilon=\alpha\Delta T/2 on the top and -\alpha\Delta T/2 on the bottom, plus an axial strain of \alpha\Delta T/2 to keep the bottom strain-free. For narrow beams, the amount of bending strain would corresponds to an effective stress of \sigma=E\epsilon=\alpha\Delta TE/2, or an effective bending moment of M=\alpha\Delta TIE/h. This applied moment would cause a deflection of \delta=\alpha\Delta T L^2/2h, assuming small deflections. (This may be the same derivation nvn used.)
 
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