Calculating Total Acceleration on an Outdoor Track

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An outdoor track measures 65m, and a runner accelerates from 4 to 7 m/s over 30m. Total acceleration is calculated to be 0.680 m/s² two seconds after the speed increase begins. The relationship between velocity and acceleration is expressed as dv/dt = a, and the equations of motion can be utilized to determine linear acceleration. Additionally, both tangential and radial accelerations must be considered to compute the total acceleration accurately.
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an outdoor track is 65m.A runner increases her speed at a constant rate from 4 to 7 m/s over a distance of 30m.Determine the total acceleration of the runner 2s after she begins to increase her speed.


the answer is 0.680m/s^2
 
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Could you show us some of your thoughts. What is the relationship between velocity and acceleration?
 
the relation is dv/dt=a.But how can i form eqn??
 
You have the linear speeds and the distance traveled while accelerating, use the equations of motion to calculate the linear acceleration - remember this is a consant acceleration.
 
may i know what's the eqn of motion that u mean??
 
teng125 said:
may i know what's the eqn of motion that u mean??

a = \frac{v^2 - v_0^2}{2d}
 
is it possible to use acce normal + acce tangential formula??
 
The formula given by cscott is for the tangential acceleration of the girl going round the track. That is a constant value.
Now you have to find the radial accelerartion, which is not constant. Do you know why ?
Ans: Because ar = v²/r and v is constantly changing (in white)
You have to find the peripheral velocity, or speed, at t = 2 sec. From that find the radial accln. Then use pythagoras' theorem with the tangential and radial accln to get the total accln.
 
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