MHB Calculating Travel Time for Light in an Optical Fiber

  • Thread starter Thread starter chrisliu1234
  • Start date Start date
  • Tags Tags
    Interference
AI Thread Summary
Light traveling through an optical fiber experiences different travel times based on its path, leading to pulse spreading and potential information loss. The fiber consists of a central core with a higher index of refraction (n1 = 1.58) surrounded by a sheath (n2 = 1.53). The discussion focuses on calculating the time difference between light traveling directly along the fiber's axis and light reflecting at the critical angle within the core. The formula for direct travel time is t = n1 * L / c, while the time for the zigzag path involves a more complex calculation. Ultimately, the change in travel time is expressed as the difference between the two calculated times.
chrisliu1234
Messages
2
Reaction score
0
Figure 35-57 shows an optical
fiber in which a central plastic
core of index of refraction n1 
1.58 is surrounded by a plastic
sheath of index of refraction n2 
1.53. Light can travel along different
paths within the central
core, leading to different travel times through the fiber.This causes an
initially short pulse of light to spread as it travels along the fiber,
resulting in information loss. Consider light that travels directly along
the central axis of the fiber and light that is repeatedly reflected at the
critical angle along the core–sheath interface, reflecting from side to
side as it travels down the central core. If the fiber length is 300 m,
what is the difference in the travel times along these two routes?

I know that I need to use t=L/v1=n1*L/c which becomes t=L/v1*cos(theta)=n1*L/(c*sqrt(1-(sin(theta)/n1)^2), but now I am stuck trying to figure the time for the question.
 
Mathematics news on Phys.org
chrisliu1234 said:
Figure 35-57 shows an optical
fiber in which a central plastic
core of index of refraction n1 
1.58 is surrounded by a plastic
sheath of index of refraction n2 
1.53. Light can travel along different
paths within the central
core, leading to different travel times through the fiber.This causes an
initially short pulse of light to spread as it travels along the fiber,
resulting in information loss. Consider light that travels directly along
the central axis of the fiber and light that is repeatedly reflected at the
critical angle along the core–sheath interface, reflecting from side to
side as it travels down the central core. If the fiber length is 300 m,
what is the difference in the travel times along these two routes?

I know that I need to use t=L/v1=n1*L/c which becomes t=L/v1*cos(theta)=n1*L/(c*sqrt(1-(sin(theta)/n1)^2), but now I am stuck trying to figure the time for the question.

Hi chrisliu1234! Welcome to MHB! (Smile)

Let's start with $t=\frac{n_1 L}{c}$ for the time to travel along the central axis.
Did you find the corresponding time?

As for the light traveling at critical angles, you're supposed to deduce a formula without theta.
Is that perhaps where your problem is? (Wondering)
 
I like Serena said:
Hi chrisliu1234! Welcome to MHB! (Smile)

Let's start with $t=\frac{n_1 L}{c}$ for the time to travel along the central axis.
Did you find the corresponding time?

As for the light traveling at critical angles, you're supposed to deduce a formula without theta.
Is that perhaps where your problem is? (Wondering)

So does change in time = t zigzag - t direct = n1^2*L/n2*c - n1*L/c?
 
chrisliu1234 said:
So does change in time = t zigzag - t direct = n1^2*L/n2*c - n1*L/c?

That looks right yes. (Nod)
 
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Thread 'Imaginary Pythagorus'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...
Back
Top