Calculating VDS(off) for Electronic Converters

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Discussion Overview

The discussion revolves around calculating VDS(off) for buck, boost, and inverting converters, focusing on the voltage across the FET during the off state. Participants explore the relationships between input voltage, output voltage, duty cycle, and the behavior of circuit components during operation.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants propose that VDS(off) refers to the voltage across the FET when it is off, questioning how to calculate this based on given parameters like Vin, Vout, and duty cycle.
  • One participant suggests that to determine VDS(off), one must analyze the voltage across the open FET during the off cycle, particularly in relation to the output voltage and input voltage.
  • There is a discussion about drawing switching waveforms to understand the voltage behavior in the circuits, with some participants expressing confusion about what to derive from these waveforms.
  • Some participants mention that the voltage at the input to the inductor in the Buck topology drops to approximately -0.7V when the FET opens, leading to questions about how this affects VDS(off).
  • Others argue that during the off state, the voltage across the FET may not be zero, as the FET presents high impedance, and thus retains a voltage difference between its terminals.
  • There is a suggestion that for the Buck and inverting circuits, VDS(off) could equal Vin, but this is contested by others who point out that the actual voltage across the FET during the off state may differ due to circuit behavior.
  • Participants discuss the implications of the diode's behavior in the circuit, particularly how it affects the voltage seen at the FET's output side when it is off.
  • One participant expresses frustration with the learning materials available, indicating a lack of clarity in understanding the concepts being discussed.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the exact nature of VDS(off) across different converter topologies. Multiple competing views exist regarding the voltage values and the behavior of the circuits during the off state.

Contextual Notes

Participants express uncertainty regarding the definitions and implications of VDS(off), particularly in relation to the behavior of diodes and the voltage levels in different circuit configurations. There are unresolved questions about the assumptions underlying the calculations and the circuit behavior.

  • #31
Ah I see, so that's just the voltage drop across there (i.e. to get the diode 'working'), not that it limits the voltage in the circuit to 0.7V.

Ok, so starting with the Buck converter:
Vout = 12V
D = 0.25
Therefore Vin = Vout/D = 12/0.25 = 48V

Vds(off) = 48-0 = 48V

Boost converter:
Vout = 12V
D = 0.25
Therefore Vin = Vout(1-D) = 12(1-0.25) = 9V

Vds(off) = Vin - ground = 9 - 0 = 9V

Inverting converter:
Vout = 12V
D = 0.25
Therefore Vin = (Vout(1-D))/D = 36V

Vds(off) = Vin + Vout = 36+12 = 48V

How's this looking?

Thanks
 
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  • #32
D44 said:
Ah I see, so that's just the voltage drop across there (i.e. to get the diode 'working'), not that it limits the voltage in the circuit to 0.7V.

Ok, so starting with the Buck converter:
Vout = 12V
D = 0.25
Therefore Vin = Vout/D = 12/0.25 = 48V

Vds(off) = 48-0 = 48V

Boost converter:
Vout = 12V
D = 0.25
Therefore Vin = Vout(1-D) = 12(1-0.25) = 9V

Vds(off) = Vin - ground = 9 - 0 = 9V

Inverting converter:
Vout = 12V
D = 0.25
Therefore Vin = (Vout(1-D))/D = 36V

Vds(off) = Vin + Vout = 36+12 = 48V

How's this looking?

Thanks

Good work. The only thing I'd change is say that for the Inverting converter, Vout is -12V, and the difference voltage Vds(off) is Vin - Vout, which gives the same answer. I can see why you did it your way, because of how the original figure is labeled.

Whew, that wasn't such a chore now, was it? :smile:
 
  • #33
Ahh right ok I see. That makes sense.

Ha, it does seem so much straight forward now I'm further down the line.

Thank you so much for your help. I'm sure you can see I would have never in a million years worked all this out myself.

You guys and this forum are great!
 

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