Calculating Velocity of a Cannonball at a Given Height

AI Thread Summary
To find the velocity of a cannonball at a height of 100 meters, the equation s(t) = 50t - 4.9t^2 must be solved as a quadratic equation. The time, t, when the cannonball reaches 100m can be determined by setting s(t) equal to 100 and solving for t. Once t is found, the velocity can be calculated using the derivative of the height function, v(t) = s'(t). The original poster initially used trial and error to estimate t as 2.73 seconds, resulting in a velocity of approximately 36.5 m/s. Understanding the proper method to solve the quadratic equation is essential for accurate calculations.
cptstubing
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Homework Statement


A Cannonball is shot upward from the ground into the air at t=0 sec. With initial velocity of 50m/s. Its height above the ground in metres is given by s(t)=50t-4.9t^2 .
----What is the velocity of the cannonball when it is 100m above the ground on the way up?
"says the book" Hint: set s(t) = 100

Homework Equations


initial velocity = 50 m/s

The Attempt at a Solution


I don't want the answer, I just want to know how it is worked out, because I know how to do it by trial and error.
If I set s(t)=100 like the book says, then 100=50t-4.9t^2
I can't solve this equation without knowing t, am I right?
Anyhow, by trial and error, i figured out t=2.73, and I think velocity at 100m = 36.5m/s...
But what is the proper way to do this without using trial and error like I did?

ie.
The question I should ask myself first is what?
1. What is t at 100m?
2. Velocity = ? at 100m?
 
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cptstubing said:

Homework Statement


A Cannonball is shot upward from the ground into the air at t=0 sec. With initial velocity of 50m/s. Its height above the ground in metres is given by s(t)=50t-4.9t^2 .
----What is the velocity of the cannonball when it is 100m above the ground on the way up?
"says the book" Hint: set s(t) = 100

Homework Equations


initial velocity = 50 m/s

The Attempt at a Solution


I don't want the answer, I just want to know how it is worked out, because I know how to do it by trial and error.
If I set s(t)=100 like the book says, then 100=50t-4.9t^2
I can't solve this equation without knowing t, am I right?
Wrong. In fact, to find the time, t, at which the cannon ball is 100m above the ground, you need to solve this.

It's a quadratic equation.
Anyhow, by trial and error, i figured out t=2.73, and I think velocity at 100m = 36.5m/s...
But what is the proper way to do this without using trial and error like I did?

ie.
The question I should ask myself first is what?
1. What is t at 100m?
2. Velocity = ? at 100m?
 
I think you deserve credit for solving by trial and improvement. I often do this myself when I can't see a simple analytic solution.

As Sammy says, it is a quadratic equation, so it's just a maths issue to solve it.

WikiP explains it here
 
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Thanks to all for the help.
I actually figured this out very quickly after a relaxing weekend.
Fresh eyes matter.
On a side note, whoever moved this thread from the 'Pre-calculus Math' section and into 'Introductory Physics Homework' section, really bruised my ego!
 
cptstubing said:
On a side note, whoever moved this thread from the 'Pre-calculus Math' section and into 'Introductory Physics Homework' section, really bruised my ego!

You'll get over it. :wink:
 
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