Calculating velocity on an inclined plane

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An object on an inclined plane accelerates at 2 m/s² from an initial velocity of zero. After one second, its velocity reaches 2 m/s, covering a distance of 1 meter during that time. The relationship between acceleration, velocity, and displacement is clarified using kinematic equations. The equation v² = v₁² + 2aD confirms that the object travels 1 meter while accelerating. Therefore, initial velocity being zero is crucial in understanding the object's motion.
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So, this particular plane is angled so that a certain object will roll at a constant acceleration of 2 m/s each second. The object's initial velocity will be zero and in one second its velocity will be 2 m/s, but will only have traveled 1 m during that duration between zero and one seconds. Is this true because the object does not travel, initially, 2 m/s?
 
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well aceleration is m/s^2 not m/s and you should use the 5 kinematic or constant acceleration equations
ie v2^2 = v1^2 +2aD
2^2 = 0 + 2(2)(D)
D=1
So the certain object will reach a speed of 2m/s with a accelertaion of 2m/s^2 in 1 meter.
And yes it is because the object is initially at rest
 
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velocity ≠ acceleration. For constant uniform acceleration a in one dimension, with zero initial velocity, the displacement s is:

s = at2/2
 
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