Calculating Vibration Frequency of 1100 kg Car with 68 kg Driver

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To calculate the vibration frequency of a 1100 kg car with a 68 kg driver, the spring constant must first be determined using the formula F = kx, where x is the compression distance converted to meters. The correct spring constant is approximately 111,000 N/m, and the total mass resting on the springs is 1168 kg. The period of oscillation is calculated using the combined mass, resulting in a value around 0.6 seconds. It's essential to ensure all units are in SI and to use the total mass for accurate results. The discussion highlights common mistakes in calculations and the importance of unit conversions.
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The springs of a 1100 kg car compress 6.0 mm when its 68 kg driver gets into the driver's seat. If the car goes over a bump, what will be the frequency of vibrations?

I tried to use the weight of the man (68 kg) and the compression distance (6 mm) to find the spring constant. I then tried to use the spring constant to find the period.

F = kx
68 = 6k
k = 11.33

T = 2(pi)(sq.rt 1100/11.33)

But I didn't get the correct answer.
 
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When you calculate k, first convert mm to m. 6.0mm = 6.0*10^-3m

When you calculate T, use the mass of the man = 68kg. not the mass of the car.
 
Also, the driver's mass is 68 kg., but you need the added weight of the driver applied to the springs. The spring constant, k, needs to be expressed in SI units, which are Newtons/m, which is why learningphysics corrected your 6 mm entry.

For the period of oscillation, you will need the combined mass of car and driver. (I'll say that the answer is in the neighborhood of 0.6 second.)
 
Last edited:
Yes, sorry you need to use:

F = kx

mg = kx (with m = 68kg) to find k...

I didn't notice the g was missing.

dynamicsolo, I'm not getting 0.6 for the period like that... are you sure about using the combined mass of the car and the person?
 
learningphysics said:
dynamicsolo, I'm not getting 0.6 for the period like that... are you sure about using the combined mass of the car and the person?

You do use the total mass (1168 kg.) now resting on the springs for this "oscillator". The figure I gave for the period is approximate because I didn't want to just provide the answer. [k should be around 111,000 N/m and sqrt(m/k) is roughly 0.1 sec.]
 
dynamicsolo said:
You do use the total mass (1168 kg.) now resting on the springs for this "oscillator". The figure I gave for the period is approximate because I didn't want to just provide the answer. [k should be around 111,000 N/m and sqrt(m/k) is roughly 0.1 sec.]

Oh, I see my problem. I was thinking the springs described were "in" the driver's seat... sorry about that.

yes, I get around 0.6. I must have been plugging in something wrong.
 
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