Calculating Wave Velocity, Mass, and Wavelength of a Guitar String

AI Thread Summary
The discussion focuses on calculating wave velocity, mass, and wavelength for a guitar string. The fundamental frequency of a steel B-string is given as 240 Hz with a length of 0.680 m, leading to a calculated wave velocity of 326.4 m/s. To find the mass of a 2 m long piece of the string, the tension of 86.8 N is used, resulting in a mass of 0.00163 kg. For the third harmonic, the wavelength is determined using the formula for harmonics, yielding a value of 834.87 m. The calculations demonstrate the application of wave physics principles in string instruments.
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Homework Statement


A. A typical steel B-string in a guitar resonates in its fundamental frequency at 240 Hz. The length of the string is 0.680 m. What is the wave velocity in the string?

B. The tension in the above string is 86.8 N. Calculate the mass of a 2 m long piece of the steel string.

C. What is the wavelength of the third harmonic of the guitar string described above?

Homework Equations


f = v/2L
Wavelength = 2L/m

The Attempt at a Solution


A. 326.4
How do I calculate B and C??
 
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B. In stretched string velocity v = sqrt(T/m) where T is the tentsion and m is the mass per unit length of the wire.
CDuring the third harminc the number of loops in the string will be 3.
 
I am sorry but I don't understand how to calculate B still.
 
Does anyone know how to do these?
 
Anyone? I need help :( I'm not figuring this out...
 
v = sqrt(T/m)
326.4 = sqrt(86.8/m). Square both the sides
326.4^2 = 86.8/m
m= 86.8/326.4^2
Mass of 2 m wire = 2m
Now solve.
 
Okay so I get 0.00163 kg...how about part C?
 
I get 834.87 for part C using wavelength = 2L/m
 
I get 834.87 for part C using wavelength = 2L/m

Wave length of third harmonic = 2L/3
 
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