Calculating Work and Power: Force of 5N on a 15kg Body at Rest

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Homework Statement


A force of 5N acts on a 15kg body initially at rest. Compute the work done by the force in: first, second, and third seconds, the instantaneous power to the force at the end of the third sec.


Homework Equations


W=fd
P=(dW)/(dt)


The Attempt at a Solution


I'm not quite sure how to work this out with just the equation W=fd, but I know work is also mass X integral of acceleration vs. position. I guess my biggest problem is not knowing where to put time...
Thanks in advance
 
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If you had an expression for the distance, s, traveled as a function of time, then you could find the work by calculate how far the body moves from t=0 to t=1, and then again from t=1 to t=2, and once more from t=2 to t=3, and the use W = Fs (using 's' instead of 'd' in order not to confuse distance with differentiation).

For the power you should notice that P = dW/dt = d(Fs)/dt = F ds/dt = F v, under the assumption that F is constant. So you can also find power if you know the speed of the body at the time in question.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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