Calculating Work and Power: Solving a Tractor Pull Problem

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A tractor pulls a wagon with a constant force of 700N at a speed of 20.0 km/h. To calculate the work done by the tractor in 3.5 minutes, the relevant equations are P=W/t or P=Fv. The correct work done is 8.16 x 10^6 J, and the power output is 3888.8 watts. The user initially struggled with the calculations but realized the need to convert km/h to m/s for accuracy. The discussion highlights the importance of unit conversion in solving physics problems.
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Homework Statement



A tractor pulls a wagon with a constant force of 700N at a constant speed of 20.0 km/h.
a) How much work is done by the tractor in 3.5min
b) What is the tractor's power output?
ANSWERS: a)8.16 x 10^6 J//b) 3888.8 watts
2. Relevant equation
P=W/t or P=Fv



The Attempt at a Solution


P=Fv
P=700N x 20.0
P=14000J

Pt=W
14000W x 210seconds=W
W=2940000J

I've been trying for over an hour now and I just can't get the answer. Any help will be greatly appreciated.
 
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Convert km/h to m/s.
 
rl.bhat said:
Convert km/h to m/s.

I realized it about 5 seconds before you posted haha. Thank you very much!
 
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