Calculating Work Done on an Inclined Plane

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A 20.0 kg dog is on a frictionless inclined plane with a constant upward force of 60.0 N applied parallel to the incline, causing it to slide 12.0 m. The discussion involves calculating the component of the applied force in the direction of the motion and the work done on the dog by that force. The formula for work, W = Fd, is mentioned, but there is confusion regarding the calculation, as one participant arrives at 720 J, which is deemed incorrect. The force of gravity is identified as the opposing force, but the lack of an angle in the problem raises questions about the calculations. Clarification on the correct approach to solving the problem is sought.
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1. A 20.0 kg dog stands on a frictionless inclined plane. A constant upward 60.0 N force parallel to the incline is applied to the butt of the dog. As a result the dog slides upward 12.0 m along the surface. (a) What is the component of the applied force in the direction of the motion? (b) How much work is done on the dog by that force? (c) What was this work done against?



2. W=Fd



3. I know the force against it is gravity, but for the actual work i keep getting 720 J and when I look in the back of the book it's wrong. Am I using the wrong equation or just working the problem wrong altogether? W = (60 N)(12.0m) = 720 N
 
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Is that all the given information? What about an angle?
 
No angle, I copied it word for word. :/
 

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