Calculating work for a weightlifter.

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The discussion centers on calculating the work done by a weightlifter lifting 390 N weights over a distance of 1.75 m. The formula used is W=F∆x, leading to an initial calculation of 682.5 Joules. Participants confirm the calculation, with one member initially doubting their result but ultimately agreeing with the original answer. The consensus is that the work done is indeed 682.5 Joules. The thread highlights the importance of double-checking calculations in physics.
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Homework Statement


A weight lifter lifts a set of 390 N weights from ground level to a position over his head, a vertical distance of 1.75m. How much work does the weight lifter do, assuming he moves the weights at a constant speed?

I am not confident in my physics skills so I am really looking for someone to grade my work and give me feedback; thanks!

Homework Equations


W=F∆x


The Attempt at a Solution


W=(390N)(1.75m)=682.5 Joules
 
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W=(390N)(1.75m) looks good!
I get a slightly different answer than your 682.5; better run it through the calculator again.
 
I would like to point out that I get the same value as OP.
 
My mistake; thanks for catching it.
 
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