a)Calculate the work performed by an external agent to move a charge of -0.39x10^-12 C from `i' to `b'
Hint: The equipotential lines shown are separated by 1 kV. Work to move a charge is the increase in potential energy of the charge. The potential energy is the potential times the charge.
b)Calculate the magnitude of the electric field at `k'.
a)-q*ΔV = Work
b) E = -ΔV/Δd
The Attempt at a Solution
a)I have tried simply plugging in the values:
q = (-0.39x10^-12) and ΔV = ([3 - +3]*1000)
And got the answer 2.34*10^-9 J
b)not really sure where to start here...