Calculating Work Needed to Stop a 1000kg Car at 100km/h

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To calculate the work needed to stop a 1000kg car traveling at 100km/h, first convert the speed to meters per second, resulting in approximately 27.78 m/s. The work required to stop the car is equal to its initial kinetic energy, which can be calculated using the formula W = (1/2)mv^2. Substituting the values, the work needed is found to be 385,800 joules. This demonstrates that to stop the car, the kinetic energy must be reduced to zero, equating work to energy.
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This should be easy...the problem asks for the amount of work needed to stop a 1000kg car traveling @ 100km/h.

I am having a hard time do to the fact acceleration,distance nor time is given.

here is how I think i need to approach this:

convert 1000km/h to m/sec

find acceleration

use Work=Mas*acceleration*Distance to find work

Here are the variables i know:

Mas=100kg
Vf = 0
V0 = 27.78 m/s

how can i find acceleration if no distance or time is given? I would think i need to find acceleration to calculate work needed to stop.

any hints?:smile:

dz
 
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Originally posted by dzem68
the problem asks for the amount of work needed to stop a 1000kg car traveling @ 100km/h.


convert speed to m/s:
100km/h * 1000m/km * h/3600s = 27.7777m/s

you have to remember the standard formula for all of these types of problems is energy in = energy out. expanded, it looks like this:
Wo + Ko + Po = Wf + Kf + Pf

W is work, K is kinetic energy, P is potential energy. For this equation, there is no work put in, no initial potential energy, no final potential energy, no final kinetic energy. With all the 0 terms removed, it looks like this:
Ko = Wf

solfing for equation:
(1/2)mv^2 = W
(1/2)(1000)(27.777^2) = W
W = 385800J
W = 3.858 x 10^5 J
 
In order to stop any object, you need to reduce its velocity to 0. That means you need to reduce its kinetic energy to 0. Work is energy so: calculate the kinetic energy. That's the work you need to do to stop the object.
 
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