Calculating Work Output from Thermal Efficiency of Car Engine

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To calculate the work output from a car engine's thermal efficiency, the power output of 600 kilowatts per hour must first be converted to kilojoules per second. The thermal efficiency formula, which is work output divided by heat input, indicates that only 30% of the energy is converted to work. The confusion arises from the interpretation of the power output, which reflects energy loss, suggesting that the initial energy input is higher than the output. Correct calculations involve adjusting for efficiency and understanding the relationship between power, work, and energy loss. Properly applying these concepts will yield the correct work output per cycle.
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Homework Statement


The power output of a car engine running at 1900 is 600 kilowatts per hour.
How much work is done per cycle if the engine's thermal efficiency is 30.0 percent

Homework Equations



thermal efficiency=w(out)/Q(hot)

The Attempt at a Solution


It wants the answer in KJ/s so i converted the kilowatts to KJ/sec then divided by rev/s then multiplied by .3. What am i doing wrong? Any help would be appreciated.
 
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Looks like you should be multiplying by 10/3.
The 600 kw/hr seems to be the power output after 70% of the initial energy has been lost.
 
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