Calculating Work to Stretch a Spring from 30cm to 41cm

Minihoudini
Messages
28
Reaction score
0

Homework Statement


A spring has a natural length of 30 cm. If a 21 N force is required to keep it stretched to a length of 35 cm, how much work W is required to stretch it from 30 cm to 41 cm? (Round your answer to the nearest hundredth.)


Homework Equations



41cm-30cm=11cm so its .11m
21n=.35mk k= 21/.35 k=60 so f(x)= 0 to .11 of 60x so the integration is 30x^2 |0 to .11

so it should be 30(.11)^2 = 363/1000


The Attempt at a Solution

 
Physics news on Phys.org
What is your question?

Yes, what you have doneis correct. Since you are told to "Round your answer to the nearest hundredth." your answer should be 0.36 Joules. (Don't forget the units, "Joules"- that's an important part of the answer.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top