Calculating Young's Modulus for a Wire

  • Thread starter Thread starter JJones_86
  • Start date Start date
  • Tags Tags
    Modulus Wire
AI Thread Summary
To calculate Young's modulus for a wire of length 4.97 m and cross-sectional area of 0.101 cm² that stretches 6.53 mm under a 0.92 kN load, the formula used is (F/A) = Y(Change in Length/Initial Length). An initial calculation yielded an incorrect value due to a miswritten area of 0.104 cm² instead of the correct 0.101 cm². After correcting the area, the user was able to arrive at the correct answer. The discussion highlights the importance of accurate data entry in calculations.
JJones_86
Messages
72
Reaction score
0

Homework Statement


A wire of length 4.97 m with a cross-sectional area of 0.101 cm2 stretches by 6.53 mm when a load of 0.92 kN is hung from it. What is the Young's modulus for this wire?


Homework Equations


(F/A) = Y(Change in Length/Initial Length)


The Attempt at a Solution



(920 N)(4.97m)/(.00653m)(.0000104 m^2) = 6.73283E10

I can't seemt to figure out what I am doing wrong... Is that answer not in Pa?
 
Physics news on Phys.org
Hi JJones_86,

JJones_86 said:

Homework Statement


A wire of length 4.97 m with a cross-sectional area of 0.101 cm2 stretches by 6.53 mm when a load of 0.92 kN is hung from it. What is the Young's modulus for this wire?


Homework Equations


(F/A) = Y(Change in Length/Initial Length)


The Attempt at a Solution



(920 N)(4.97m)/(.00653m)(.0000104 m^2) = 6.73283E10

I can't seemt to figure out what I am doing wrong... Is that answer not in Pa?

In the problem statement it says the area is 0.101 cm2, but in your calculation you use 0.104cm2. Which one is correct?
 
LOL, well that was my problem then. For some reason I wrote down .104 cm... After correcting it, I got the right answer. Thanks!
 
Glad to help!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top