# Calculation of the force exerted by a liquid

## Main Question or Discussion Point

Question: The height of the given vessel is h,and the width of the given vessel is b (as given in the diagram). The density of the liquid is r.Find the force exerted by the liquid on the slant wall.

Relevant formulae : P = F/A
F = Vdg

An attempt at the solution : I had tried taking a differential slice of the liquid and then integrating. But I am having trouble handling the alpha part. Where does the angle alpha fit into this question?

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Bystander
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Check the problem statement for any details regarding the force. What you've posted does NOT specify whether it's the normal force or force in the "x" direction.

Check the problem statement for any details regarding the force. What you've posted does NOT specify whether it's the normal force or force in the "x" direction.
It's the force in the x-direction. Sorry for not mentioning earlier.

Bystander
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One step at a time: what does "P" depend upon?

P,or the pressure,depends upon the area A and the force F.

Bystander
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You're trying to find "F" by looking at "P." What else determines "P?"

Pressure depends upon the height from the free surface of the liquid h,the density of the liquid d and the acceleration due to gravity g.

Chestermiller
Mentor
Pressure depends upon the height from the free surface of the liquid h,the density of the liquid d and the acceleration due to gravity g.
Is P the same at all depths?

Chet

Nope,pressure isn't the same at all depths. As depth increases,so does pressure.

jbriggs444