Calculus 3 question- don't even know how to approach this problem

krtica
Messages
50
Reaction score
0
Find the mass of one turn of wire in the form of a helix with a linear density e^(-z) in lbs/ft.


Would I write as <e^(-z)*cost,e^(-z)*sint, t>? Maybe?
 
Physics news on Phys.org
The first thing to check for is units. The problem with your proposed solution is that the x and y components have units of weight, while the z component has units of length.

What is given is the density (ratio weight per length), so to get weight just multiply the density by the length. The arclength of a curve is given as the integral of the modulus of the derivative of the curve. So just put the density inside the integral and solve.
 
krtica said:
Find the mass of one turn of wire in the form of a helix with a linear density e^(-z) in lbs/ft.Would I write as <e^(-z)*cost,e^(-z)*sint, t>? Maybe?

First, you should note that the problem is not well posed. It makes a difference which turn of the wire since the density is not constant. You want to calculate

\int_C \delta(x,y,z)\ ds

with appropriate units.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top