Calculus airplane related rates problem ( cosine rule)

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SUMMARY

The discussion centers on a related rates problem in calculus involving an airplane moving at a constant velocity of 120 meters per minute (2 meters per second) at a 60-degree angle from the horizontal. The student is 5 meters away from the airplane's starting point. The equation derived for the distance \( r \) between the student and the airplane is \( r^2 = (2t)^2 + 5^2 - 2(2t)(5)\cos(120^\circ) \). The goal is to differentiate this equation with respect to time to find the rate of change of distance \( \frac{dr}{dt} \) in meters per second.

PREREQUISITES
  • Understanding of related rates in calculus
  • Familiarity with the cosine rule in trigonometry
  • Ability to perform differentiation with respect to time
  • Knowledge of converting units (e.g., meters per minute to meters per second)
NEXT STEPS
  • Study the application of the cosine rule in related rates problems
  • Practice differentiation techniques in calculus
  • Explore examples of related rates problems involving angles and distances
  • Learn about the implications of velocity and angle in motion problems
USEFUL FOR

Students studying calculus, particularly those focusing on related rates problems, as well as educators looking for examples to illustrate these concepts in a practical context.

jaychay
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A student has test his airplane and he is far from the airplane for 5 meter.He start to test his airplane by letting his airplane to move 60 degree from the horizontal plane with constant velocity for 120 meter per minute.Find the rate of distance between the student and the plane when the plane is moving 60 degree from the horizontal plane for 10 meter in the air ?

Please help me
I have tried to solve the answer many times but I cannot do it
Thank you in advice
 

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Are you translating this to English from another language? I assume the problem wants to know the rate of change of the distance between the plane and student w/respect to time.

note 120 meters/min = 2 meters/sec

let $r$ be the distance between the student and the airplane at any time $t$ in seconds

$r^2 = (2t)^2 + 5^2 - 2(2t)(5)\cos(120^\circ)$

take the derivative of the above equation w/respect to time, then determine the value of $\dfrac{dr}{dt}$ in meters/sec
 
skeeter said:
Are you translating this to English from another language? I assume the problem wants to know the rate of change of the distance between the plane and student w/respect to time.

note 120 meters/min = 2 meters/sec

let $r$ be the distance between the student and the airplane at any time $t$ in seconds

$r^2 = (2t)^2 + 5^2 - 2(2t)(5)\cos(120^\circ)$

take the derivative of the above equation w/respect to time, then determine the value of $\dfrac{dr}{dt}$ in meters/sec
Thank you very much
 

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