(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find the radius of convergence and the interval of convergence of the series sigma[n=1,inf] ((3x-2)^n/(n^2*3^n))

2. Relevant equations

3. The attempt at a solution

sigma[n=1,inf] ((3x-2)^n/(n^2*3^n))

I applied the Root Test

p=lim n->inf |(3x-2)^n/(n^2*3^n)|^(1/n) = lim n->inf |(3x-2)/(3n^(2/n))| = 0

So the series Converges but I'm lost as to how to come up with the radius of convergence or the interval of convergence

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# Homework Help: Calculus II - Power Series

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