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## Homework Statement

Find the radius of convergence and the interval of convergence of the series sigma[n=1,inf] ((3x-2)^n/(n^2*3^n))

## Homework Equations

## The Attempt at a Solution

sigma[n=1,inf] ((3x-2)^n/(n^2*3^n))

I applied the Root Test

p=lim n->inf |(3x-2)^n/(n^2*3^n)|^(1/n) = lim n->inf |(3x-2)/(3n^(2/n))| = 0

So the series Converges but I'm lost as to how to come up with the radius of convergence or the interval of convergence

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