Calculus II Problem: Dams and intergration by slicing

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The discussion focuses on calculating the force exerted on the Deligne Dam by water pressure using integration techniques. The dam's wall is defined by the curve y = 0.6x^2 and the line y = 164, with water density set at 1000 kg/m^3. Participants suggest expressing the width of the dam as a function of y to derive the integrand. The process involves finding the volume of the dam, calculating mass from volume and density, and then converting to weight using the acceleration due to gravity (9.8 m/s^2). Overall, the conversation centers on applying integration by slicing to determine the dam's structural forces.
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The Deligne Dam on the Cayley River is built so that the wall facing the water is shaped like the region above the curve y=0.6 x^2 and below the line y= 164 . (Here, distances are measured in meters.) The water level can be assumed to be at the top of the dam. Find the force (in Newtons) exerted on the dam by water pressure. Water has a density of 1000 kg/m^3 . Since this is a metric problem, you must multiply the mass to be lifted by 9.8 m/sec^2 to convert to a weight.
First give the integrand expressed in terms of y (the width of the dam must be expressed as a function of y).
 
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anyone?
 
i would find the volume of the damn using D=\frac{M}{V}
I'm not sure on that. Once you get volume,
do volume times density to get mass. Multiply mass by 9.8 m/s^2. I think that's it, but could be wrong.
 
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you also might be able to get the width of the dam by finding the arclength of the dam.
 
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