Calculus-integration over mass

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Integration in calculus can extend beyond simple limits of independent variables to include mass, area, and line integrals. For moment of inertia, the integration involves small mass elements (dm), represented as dm = ρ dV, where ρ is the mass density, leading to the total mass M = ∫ dm = ∫ ρ dV. When density is uniform, this simplifies to M = ρV. Line and surface integrals are commonly used in electrostatics, where infinitesimal quantities like line charge (dλ) and surface charge (dσ) are defined similarly to mass elements. Understanding these integrals requires visualizing how different physical quantities relate to their respective dimensions.
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There are certain integrals which say integration over all m ,integration over all area,integration over line. I am confused with this. In calulus i am comfortable with integration with limits of an independent variable and the
integration results in the area under the curve. But in doing the moment of inertia of a solid about the axis a small dm is present inside the integral
and we say to integrate it for M. What is this integration about M exactly .

Similarly what is integration over line and area. How can i visualize this?
 
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chandran said:
There are certain integrals which say integration over all m ,integration over all area,integration over line. I am confused with this. In calulus i am comfortable with integration with limits of an independent variable and the
integration results in the area under the curve. But in doing the moment of inertia of a solid about the axis a small dm is present inside the integral
and we say to integrate it for M. What is this integration about M exactly .

Similarly what is integration over line and area. How can i visualize this?

For an infinitesimal mass, what you have is

dm = \rho dV

where \rho is the mass density. So, in general, the mass of the object is the integral of dm over the volume that is occupied by that object, i.e.

M = \int dm = \int \rho dV

If the density is uniform throughout the mass, then you can factor the density out of the integral and all you have, after doing the integral is

M = \rho V

which is what you are familiar with as the mass of the object.

The line and surface integral usually comes in in electrostatic. What you are doing actually is doing a line charge and surface charge integral. So instead of dm, you have d\lambda or d\sigma where \lambda is the infinitesimal line charge defined as

\lambda = Q dl

and d\sigma is defined as

d\sigma = Q dA.

You'll notice that this is of similar form that we had for dm, where the "nature" of the quantity (i.e. mass M, or charge Q) is paired with the "dimension", i.e volume or length or area.

Zz.
 
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chandran said:
Similarly what is integration over line and area. How can i visualize this?

There is a thread about this going on in the math section. Here's the link,

https://www.physicsforums.com/showthread.php?t=127425
 
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