Calculus Problem Help: Tangent Line & Demand Curve Calculation

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help!Calculus problems

1)Find the equation of the tangent line to f(x) = (x - 6)8 at the point where x = 7.




2)The demand curve for a product is given by
q = f(p) = 5,000e-0.30p,
where q is the quantity sold and p is the price of the product, in dollars. Find f(6) and f'(6).
 
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I have a hunch that maybe you did not write the problem correctly.
 
Also, nobody is going to do your homework for you, so you have to put your work down if you want help.
 
u probably got the question wrong the given equation is linear. tangent at any point of linear equation is that line itself. plus u'll never learn if r going to have someone else do ur HW.
 
I suspect that the first problem involved (x-6)8.

However, there is no work shown so don't expect anyone to do your work for you.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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